0.20 + 0.50 = 0.70 43.20 / 0.70 = 61 5/7 61 x 0.70 = 42.70 43.20 - 42.70 = 0.50 Ans = 61 + 1 = 62 50-cent coins

Subtract one 50-cent coin from $43.20 to ensure that there will always be more 50-cent coins than 20-cent coins. $43.20 - $0.50 = $42.70 = $0.70 × 61 = ($0.50 + $0.20) × 61 There are 62 50-cent coins

Pri 1?

Is it this? 20 + 20 + 20 + (3.14 x 20) = 122.80 The 3 semi circles could add up to be a semicircle of the big square of 20cm by taking the 3 circles' diameters add up to be the length of the side (20cm) ; while the top lines add up to the other breadth (20cm)

I think need to divide 62.8 by 2 coz they are semicircles not the full circle (20 x 3.14)÷2=31.4 20+20+20+31.4=91.4

Justmiclara, no lah... Asking on behalf of a friend

Thanks everyone for your inputs! Appreciate much!

I had never thought of it before but it is really true that the circumference of three semicircles whose diameters have a sum of 20 is equal to the circumference of a semicircle whose diameter is 20. That question in itself is a good assignment. Thank you for this.

Lol thx Shoelle Eng-Goh! Forgot to divide by 2!

My pleasure :)

Hi Xavier Sng, may I know why for the pupils of 6a , you added another 6 although the there are already six parts in the model ?

Ok I got it. Thank you so much Xavier Sng. Appreciate your help!! Have a great wkend. 😊

You are most welcome. You have a brilliant Sunday yourself. Regards

Thks.

Happy to help. 加油。

Thank u very much

Concept here is that because triangles B and D share the same base and their heights form the breadth of the rectangle, the sum of their areas is half the area of the rectangle. The same thing applies to triangle A and C. That's why A+C = B+D

Thanks u very much

Thank for the explainatiob.