Cholan Kanimozhi
Asked 9 years ago

SG chevron_right Primary 4 chevron_right Fractions

P4.help pls

Replies 6

Shaoyang Brandon

Hi. See image for details. :)

6 years ago
Cholan Kanimozhi

can u pls explain how it became 10 units

6 years ago
Shaoyang Brandon

Before: Jay has 2 times as many as Ryan. So, Jay has 2 units, Ryan has 1 unit. Total units is 3. After: Jay has 2/3 of Ryan. So, Jay has 2 units, Ryan has 3 units. Total units is 5. Their total marbles remains the same throughout. So, how can total units change from 3 to 5? The answer: Make the total number of units to be 15 for 'before' and 'after'. 15, because it is a common multiple of 3 and 5 for the total units. Hence, in the 'before' diagram, Jay will have 5 x 2 = 10 units. :)

6 years ago
Cholan Kanimozhi

thanks a lot for ur clear exp.

6 years ago
Jasmine Tang

This is done by my Daughter. She is a p6 girl from Woodlands Ring Primary School.

6 years ago
Alex Lum

6 years ago
Cholan Kanimozhi

can u pls explain how it became 10 units

6 years ago
Shaoyang Brandon

Before: Jay has 2 times as many as Ryan. So, Jay has 2 units, Ryan has 1 unit. Total units is 3. After: Jay has 2/3 of Ryan. So, Jay has 2 units, Ryan has 3 units. Total units is 5. Their total marbles remains the same throughout. So, how can total units change from 3 to 5? The answer: Make the total number of units to be 15 for 'before' and 'after'. 15, because it is a common multiple of 3 and 5 for the total units. Hence, in the 'before' diagram, Jay will have 5 x 2 = 10 units. :)

6 years ago

Adrian Ng
Asked 9 years ago

SG chevron_right Primary 3 chevron_right Number and Algebra

Making it visual...P3

Replies 0

Firdaus Omar
Asked 9 years ago

SG chevron_right Primary 3 chevron_right Number and Algebra

Help needed

Replies 14

Ariel Lim Ah Ping

6 years ago
Firdaus Omar

Thanks

6 years ago
Firdaus Omar

Sorry answer David shld be 23 .. typo error

6 years ago
Raymond Ng

6 years ago
Firdaus Omar

Thanks Raymond .. can be very challenging pri 3 question

6 years ago
Raymond Ng

I beg to differ. I would tend to think it all boils down to question exposure ☺

6 years ago
Izam Marwasi

Firdaus...for PR 3...can draw step by step model....

6 years ago
Firdaus Omar

Noted

6 years ago
Firdaus Omar

Exam fever and we parents are more worried .. thanks for the advice u guys .. appreciate it

6 years ago
Izam Marwasi

A+B+D->51 A+D->34 B+D->40 ---------------------- A+B+D+D->74 51+D->74 D->74-51= 23(ans)

6 years ago
Andy Lim

(A+D)+(B+D)-(A+B+D) =34+40-51 =23

6 years ago
Andy Lim

Complicated Maths made easy. From Dr. Andy Lim 😊😉

6 years ago
Ariel Lim Ah Ping

Oops! Thanx all. I minus salah. Should be 23 not 33. Careless. But my working correct. Please give me one out of 2 marks

6 years ago
Sofi John

Ani+Davi=34 51-34=17 Bala+Davi=40 51-40=11 Ani+Bala =17+11=28 51-28=23. David=23.

6 years ago
Raymond Ng

I beg to differ. I would tend to think it all boils down to question exposure ☺

6 years ago
Izam Marwasi

Firdaus...for PR 3...can draw step by step model....

6 years ago
Firdaus Omar

Noted

6 years ago
Firdaus Omar

Exam fever and we parents are more worried .. thanks for the advice u guys .. appreciate it

6 years ago
Andy Lim

Complicated Maths made easy. From Dr. Andy Lim 😊😉

6 years ago

Candy Chan
Asked 9 years ago

SG chevron_right Primary 6 chevron_right Number and Algebra

How to do this question? TIA .

Replies 6

Shaoyang Brandon

Hi, Candy Chan. If 20% of the beans are red, 80% of the beans are green. Hint 1: Calculate the mass of the green beans. (0.8 x 2105kg = :) ) This mass, if you observe, has no change to it throughout the problem. So, if :) represents 70% now, what is 100% mass? Once you get this 100% mass, take the difference with 2105kg. You will then know the mass of red beans were bought. Try this hint out and let me know.

6 years ago
Candy Chan

Hint 1 : 1684kg, but the number is very big .

6 years ago
Shaoyang Brandon

You are right! It is 1684 kg. You got the mass of the green beans!

6 years ago
Candy Chan

So, 421kg is the mass of red beans?

6 years ago
Shaoyang Brandon

Yes...but you don't calculate it now. It will confuse you.

6 years ago
Shaoyang Brandon

New mass of beans - 2105kg of beans = additional mass of red beans bought.

6 years ago

Aini Rizal
Asked 9 years ago

SG chevron_right Primary 5 chevron_right Fractions

Assistance needed for this qn pls, thks in advance...

Replies 4

Shaoyang Brandon

Hi, Aini Rizal. Here is the solution. :) What difficulty did you have with the problem?

6 years ago
Yeo See Yeong

Another method.

6 years ago
Aini Rizal

Thks all for the help. Am trying to absorb the pcs together. The tricky part for me is the fraction comparisons betw the 3

6 years ago
Kwang Huang Sim

Hi hope this help.

6 years ago