Hi. What happened to D?

C made quad as many as D

I see. :) I assume quad means 1/4 if that is what you mean. What about E?

Sorry for the error twice thrice then should b fourth time and E should b five time

I see. :) So, is the problem as follows? A is twice of B. B is thrice of C. C is 4 times of D. D is 5 times of E. A+B+C+D+E = 150 cars Then, the solution is as follows. Hint: Start with E first. Let 1 unit be the number of cars Company E produces. E - 1 unit D - 5 units C - 4 x 5 units = 20 units B - 3 x 20 units = 60 units A - 2 x 60 units = 120 units Total units: 1+5+20+60+120 = 206 Hmm...did you come up with this problem? If so, you can modify it such that the total cars produced is 206 or in multiples of 206. :) Then, the total cars produced can be divided without remainder. If not, buying a fraction of a car is not practical. :)

U r right! Thank u

Oops. My addition is wrong.

please write the whole question again..

Ten place is 6 , one place is 3 .. Ans:63

But 63 is odd no

64

63 is not an even number. Is the question wrong?

63

6 n 3

Opps miss the even number hmm then qnd wrong?

No such number, unfortunately. When your ones digit is even and your tens digit is twice that of the ones digit, you end up with even digits. Even digits add up to even values. 9 is an odd value so this question has no such number.

Agreed , is it question print wrongly ?

Think the question set wrongly. Cos even number means can be divided by 2

I am a 2-digit even number. The sum of 2 digits is 9. The digit is the ones place is twice the digit in the tens place. What is the number? 36 (Original question edited)

I am a 2-digit odd number. The sum of 2 digits is 9. The digit is the tens place is twice the digit in the ones place. What is the number? 63 (Original question edited)

Yes to Eva & H Jen. . My girl got the question wrong

63 is not an even number.

you need to use guess and check to solve this questions.. for the primary school Number in the 10 place / Number in the 1 place 2/1 2+1 = 3 wrong 4/2 4+2 = 6 wrong 6/3 6+3 = 9 right

Hi. How do you derive 10u for 10c (in the end box)? Thank you

You can use 1u instead.

Now I understand. Thank you :)

Hi, Arlene Tan. Refer to the image for the model to find the number of coins respectively at first. What challenges did you encounter in solving this problem? #SB50cent20cent #SB37removed

I think it was quite confusing to apprehend which to find first. Thank you for having such detailed working!