Hi. The hint here is to see that for every 2 units of corn cobs, there are 3 units of sausages. So, there are 5 units of corn cobs and sausages. Split these 5 units into 10 smaller units. If you wonder why, read on. 1/3 of the food are wings. Since 2/3 of the food are corn cobs and sausages and there are 10 smaller units for them, the number of smaller units for chicken wings is 1/2 of the smaller units of sausages and corn cobs. You will get the following number of small units. Corn cobs - 4 Sausages - 6 Wings - 5 With this, you can now solve for the question. :)

Thanks for your explanation. It helps☺️

Thank you Raymond Ng

Zhong Shu Hao, can help? Maybe my boy copied down the working wrongly. 😑

12 + 10 + 60 = 82

Raymond, can explain why?

The number of pencils that Mr Koh has is: 10 more than multiples of 12. 2 more than multiples of 10. Hence, the least number of pencils Mr Koh has is 10+12=22. Now, since 22 is not within the range of 50 to 120, we need to add a common multiple of 10 and 12. The lowest common multiple of 10 and 12 is 60. 22 + 60 = 82 Since 82 is within the range, 82 is the final answer.

Hi, here's an explanation of the original solution given by the tutor from the centre. If we can find how many pencils each girl gets in Case 1, then the answer can be found easily. Since the remainder of 10 in Case 1 can be completely evenly distributed to the 10 girls in Case 2, then the remainder of 2 in Case 2 should come from the 11th and 12th girl in Case 1, each contributing 1. The rest of the pencils from these 2 girls in Case 1 are then evenly distributed to the 10 girls in Case 2, say the 11th girl gives to the first 5 girls in Case 2 and the 12th girl gives to the last 5 girls in Case 2. From the above, each girl in Case 1 has 1+5u of pencils, so the possibilities are 6, 11, 16, ... But since 12x11=132 is already greater than the upper limit of 120, therefore 6 is the only option. 6x12 + 10 = 82

Which grade is this btw?

P5

I used a shortcut method above. In such problem, at Pri level, listing might be most appropriate, as below: ..., 22, 34, 56, 70, 82, 94, ... ...,12, 22, 32, 42, 52, 62, 72, 82, 92, ...

List of the multiples, right? I told my boy too. But his tutor from the centre told the class it will take a long time and taught them to use the method above. My boy doesn't understand and of course neither do I.

At their level, the list can be done within a matter of seconds, so I beg to differ. If they want shortcut, then isn't mine shorter than what they did? ☺ My advice? Just do listing. It's the safest

I agree so too, Raymond. Thanks.

Sorry, Shu Hao. I understand about finding the common multiples but I understand why must add in 22.

because it is the "22" which caused the remainder when divided by 10 or 12.

refer to Rye Tan's diagram below

Rachel - 12 units because Rachel has twice as many as Caroline Caroline - 6 units Denise - 1 unit Denise has 154 stickers lesser than Rachel. Difference in units of Denise and Rachel is 11. So, 11 units = 154 1 unit = 14. You can now solve for Caroline's number of stickers. :)

thanks.

Hi Bee Yen, since this is an MCQ, just need to observe that 84 is the only option that is divisible by 6, hence it's the answer.

(A) 3/4=9/12. Not 6/12. Box a contained more sand I think your working for (A) is wrong...

9u=135 That's why divided by 9

😊

Since the qn stated "are of the same size" means just remind ur kid that both denominators must have the same units, ie 12 units. Draw the model to have a clearer picture. Box A --- 9 units of sand Box B ---- 5 units of sand

oh ... ya hor .... i overlooked also ... tks ivin 😘😘

at 1 st i overlooked 3 x 3 = 6 (based on isaac wrote 😅😅😅) tats y duuno y not ÷ 6 is ÷ 9 😕😕 now i know 😊😊

thank you very much ... i think i need to do some more practice also 😥😥

It's ok. Common mistake... Often then not we overlooked the easier ones.

thank you ann 😘😘