Sorry the answer is 35 stickers
12n-1=9n+8
3n=9
n=3
n=>no of books
12n-1=36-1= 35 stickers
9n+8= 27+8= 35 stickers
6 years ago
Xavier Sng
You are welcome. Regards
6 years ago
Firdaus Omar
Got the picture now .. maths nowadays are very weird
6 years ago
Xavier Sng
Yes, mathematics for our primary school students today can be rather challenging.
6 years ago
Firdaus Omar
Glad there's social media to help us parents .. thanks a lot
6 years ago
Xavier Sng
Please don't mention it. We all learn and progress together to help the kids.
6 years ago
Firdaus Omar
6 years ago
Izam Marwasi
Xavier Sng..
Pls check this
Case 1-> 8 books
8x12 stickers + 11(1 short of 12) = 107 stickers
This was my initial working as I did not read the QN saying there both have same no of books.
But if the QN state that both of them have diff no of books but same amount of stickers..->
What will the working be?
Case 2
11 books
11x9= 99 + 8= 107 stickers
6 years ago
Firdaus Omar
Noted
6 years ago
Xavier Sng
Hola Izam.
The lowest common multiple of 9 and 12 is 36, all multiples of 36 will fit the scenario you raised on the condition that the number of books that are decorated by Elaine and Jennifer are not the same.
107 is the third multiple of 36, minus 1.
6 years ago
Izam Marwasi
Thank you Xavier Sng..understand now..
6 years ago
Xavier Sng
Thank you Izam.
6 years ago
Soo Vei Li
With 9 stickers in each book and 8 left over, we can use the left overs to add 3 more stickers to each book to make 12 each with 11 left over.
6 years ago
Joyce Teh
Asked 9 years ago
SG
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Primary 6
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Number and Algebra
Hi, need help with this question. How to solve this without using Algebra? Tk u!