Every 3 boys there is a girl, means 3 boys get 6 balloons and 1 girl get 3 balloons, thats a total of 9 balloons handle out per set 279 / 9 = 31 sets since boys are thrice, so 31 X 3 = 93 boys

Tks all :)

No idea as well... P1 question some more

Number bonds. Not pattern. Edit: my mistake. Did not realise the black dots have to be same answer.

This question has been posted before. We won't answer it again. Pls scroll below for answers

I can't find it leh. Thought there was some missing number or something

A few method Think this is more suitable for P1 11-7=4 10-2=8 11+2=13 7+10=17 All add together 42 Same as the other side There's another method (11-7-2)x10 (16-9-3)x5 20 But this is a bit difficult for p1

Thank u

42 or 3

Let X be the number, make two equations, LHS=RHS.

Is this confirmed as a P1 question? In an earlier post of this very question, the OP said that it was sent to her from a friend. Don't think it was confirmed if from a school, or enrichment centre, or some other source. And I don't think the OP ever came back with the recommended answer from whoever set this question.

https://m.facebook.com/photo.php?fbid=10153242137220698&id=601275697&set=o.259454320877898&source=43

This is a dumb question

Dun think this question is pitched at the right level.

The first answers were 12 and9

Kelley Yeong

Sorry. I didnt know. I will scroll down to have a look

P1 haven't learn multiplication right?

Dannis Chan, they did learn multiplication in p1

Showing this to highlight the flaws in the question. Additionally there should be one "marking scheme" only. Hence, definitely someone must have copied from somewhere without forethought. If it's P1, there shouldn't be algebra in the first place. Teacher who set this kinda question is surely sending the school and its HOD a msg of "promote me" but in the expense of all children who merely starting to learn addition and subs traction in P1. No matter how you look at it, it's just awful.

Relook at my working again. Thanks.

Ok tq.

They haven't learnt how to solve for unknown

Chong Ji Lian if it's known then there is absolutely needless to solve isn't it? No matter from whichever perspective u view this question, one still has to solve for an unknown.

Is D the mid-point of the rectangle length-> any clue that I miss Yeo See Yeong

Thanks!

U are right izam. I just saw the 2 ' to the left and right of D and assume D is the mid point. I revised and hope it is correct.

Actually the individual base of the yellow∆ and the white∆ doesn't matter as long they add up to 36cm as the height of both yellow/white ∆ are known... I will calculate as ∆yellow+∆white as one with a height of 16cm.+4cm ..should get the same answer...haahaa...still digesting this figure...little bit blank now..

Triangle 1: 36 x 12 x 0.5 Triangle 2: 16 x 16 x 0.5 Triangle 3: 20 x 4 x 0.5 Rectangle: 36 x 16 DEF = Rectangle - sum of the triangles. :)

White - 109+4P Red - 5P 109+4P+5P=280 -> 9P=171 -> P=19 Red : 5x19=95

280-109=171 1u = 171/9=19 5u = 19x5=95 use model to help your child😊