Zeenath Chamboli
Asked 9 years ago

SG chevron_right Primary 4 chevron_right Number and Algebra

P4 question .. Please helpThank you

Replies 2

Ida Tan

Assume all questions answered correctly : 30x3 = 90 90-62=28 28 divided by 4 (difference in value) = 7 Number of incorrect answers=7 30-7 = 23 (number of correct answers )

6 years ago
Zeenath Chamboli

Thank you Ida Tan

6 years ago

Khim Lim
Asked 9 years ago

SG chevron_right Primary 6 chevron_right Fractions

Nowadays math question are so difficult. Can somebody pls help.thks.

Replies 16

Izam Marwasi

Adam beads -> 15u (Multiple of 3&5) Case 1 Adam gave 1/3 Adam left 2/3= 15u×2/3= 10u Adam 10u Rahmat 10u+70 Case 2 Adam gave 1/5 Adam left with 4/5×15=12u Adam 12u Rahmat 12u+10 Rahmat values in both cases are equal.. 12u+10=10u+70 12u-10u=70-10 2u=60 1u= 30 Adam had 15u=15×30=450 beads(answer)

6 years ago
Jasper Tay

Would it be more appropriate if we say the total remains the same. Ie... Case 1 10u + 10u +70 Case 2 12u + 12u + 10 Hence 20u + 70 = 24u +10 4u = 60 1u = 15 Adam has 15u which is 15x15 = 150 + 75 = 225?

6 years ago
Izam Marwasi

Yup... Jasper Tay..I think u are right.. I am.still figuring out why my answer could be wrong.....thank you..

6 years ago
Jasper Tay

My reason is in both cases .. what Adam give to rahmat are different. However since they share the beads then in both cases the total of adam and rahmat in both cases are the same.

6 years ago
Izam Marwasi

Agreed.. I check back my answer is wrong...was figuring out till I saw your solution.. Yes u are right.... Cheers...thanks

6 years ago
Jasper Tay

My pleasure izam

6 years ago
Khim Lim

Thank you so much

6 years ago
Jason Oon

Find difference between 2 cases: 1/3 - 1/5 = 5/15 - 3/15 = 2/15 70 - 10 = 60 2u -> 60 1u -> 30 15u -> 30 x 15 = 450 beads

6 years ago
Jasper Tay

Lets check if the above can be done. Case 1 : Rahmat has 70 more than Adam if Adam give 5U which is 1/3 of what he has. So Adam would have 10U remaining and Rahmat has 10U +70 Total beads = 10U + 10U + 70 = 670 ( assuming 1U =30) Case 2 : Rahmat has 10 more than Adam if Adam gives 1/5 of what he has. Hence Adam would have left 12U and Rahmat has 12U+10 Assuming 1U = 30 then Adam would have 360 and Rahmat has 370 total = 730 Seems like there is a discrepancies of 60 here. I like to see where I have gone wrong after checking the workings.

6 years ago
Izam Marwasi

Nope you're are right the above check back is wrong answer.. Ans is 225.. I've done the check back..I am outside now..couldn't provide the check back..

6 years ago
Izam Marwasi

Adam 225-75= 150 Rahmat ->220 Total ->370 Adam Before-.>225 Rahmat Before-> 220-75=145 145+225=370 Case2 Adam-.>225-45=180 Rahmat 180+10= 190 Total->370 Before Adam 225 Rahmat-> 190-45=145 Total-.> 225+145=370

6 years ago
Izam Marwasi

The difference of 60 as per Jason Oon working is Adam(225-145=60) having 60 more than Rahmat ..

6 years ago
Jasper Tay

Thanks Izam. I was trying to use Jason numbers to justify the statements on the check back.

6 years ago
Izam Marwasi

Understand..

6 years ago
Jasper Tay

6 years ago
Jasper Tay

6 years ago
Izam Marwasi

Agreed.. I check back my answer is wrong...was figuring out till I saw your solution.. Yes u are right.... Cheers...thanks

6 years ago
Jasper Tay

My pleasure izam

6 years ago
Izam Marwasi

Understand..

6 years ago

Khim Lim
Asked 9 years ago

SG chevron_right Primary 6 chevron_right Fractions

How can I check how do you do this?

Replies 4

Izam Marwasi

2/5 of 25= 10 10girls×3u =30u 15boys×1u=15u 15u+30u=45u=135 u=135÷45=3 Each girl had 3u=3×3=9 books each(ans)

6 years ago
Khim Lim

Thks for the help

6 years ago
Shaoyang Brandon

Hi! You can refer to the 2 images below for an explanation.

6 years ago
Shaoyang Brandon

6 years ago

Adrian Ng
Asked 9 years ago

SG chevron_right Primary 6 chevron_right Number and Algebra

Making it visual...

Replies 0

Angela Oh
Asked 9 years ago

SG chevron_right Primary 4 chevron_right Number and Algebra

Need help on this P4 Maths question. Thank you.

Replies 2

Ida Tan

6 years ago
Angela Oh

Thank you, Ida.

6 years ago