7r -> 70
r -> 10
2r -> 20
Area of 2 squares
= 2 x 20 x 20
= 800 cm2
Area of 4 rectangles
= 4 x 20 x 10
= 800 cm2
Area of 3 semi-circles
= 3/2 x π x 10 x 10
= 471 cm2
Total area
= 800 + 800 + 471
= 2071 cm2
If you looked at the dotted lines I've drawn, the shaded triangles are same as the unshaded ones. Hence, total area = 300 x 2
6 years ago
Mavis Low
Yup got it, thanks!
6 years ago
Yeo See Yeong
Is it correct to say that, no matter Joe many triangles there are in ABFE, as long as their height is the same and meet the line EF (where the opposite triangle height is), the shaded area will always be half of the rectangle?
6 years ago
Xavier Sng
You are perfectly correct, Mister Yeo. It is also important that the combined bases of the triangles concerned add up to equal AB, the length of the figure.
6 years ago
Theresa Lim Sin Jin
Asked 9 years ago
SG
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Primary 6
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Number and Algebra
P6 A* Math question. Need hlp.Thanks in advance
Replies
6
Xavier Sng
6 years ago
Xavier Sng
6 years ago
Theresa Lim Sin Jin
Oh wow !! What an effort !!
Really appreciate the detial.
Thanks million.
6 years ago
Xavier Sng
You are most welcome. I tried to solve it without listing / guess-and-check, but after much exploration I had to throw in the towel. What I tried to do here is to make use of divisibility rules to eliminate unlikely number of printers sold on day one. However the divisibility rules are not taught in primary school. It used to be in secondary one textbooks but the textbooks had been revised and the rules are no longer featured. Please let me know if you wish to learn the divisibility rules here.
6 years ago
Theresa Lim Sin Jin
Thanks again . Will let u know when need more detail. 😊
6 years ago
Xavier Sng
Please don't mention it. Anyway it takes a while to type the divisibility rules out and to show how they are applied :-)
6 years ago
Hu Sophia
Asked 9 years ago
SG
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Primary 5
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Number and Algebra