Put the square A in Square B. From there quite direct.

Nice - it's testing the fundamental concept that squares have equal sides

Thannks Michael Tan for the solution. Its perfect 😊

Michael Tan, can you pls help me with this one? Thanks!

Thanks Raymond Ng

Delia Gong Hsien-Ai just saw. Visiting someone at hospital. Okay..raymond has solved :)

Sir...don't understand. .why divide by 4 . sides are not equal right?

4 is the width of the bar... see my colourful diagram at the top... 😭

147: extra green beans for 3u 147 / 3 = 49 extra green beans per unit 147 + 49 = 196 Minus all extra beans: 772 - 196 = 576 9u = 576 1u = 64 5u = 320

Thank Vincent n Jason.:)

Thanks! But can you explain?

6x40: total mass of 6 4x12: excess mass of the first 4 using the last 2 average as a gauge ÷6: to get average mass of last 2

Got it, thanks!

Thanks Vincent!

Why $576 x 3/10?

That's part of the money that is left, after Yusof spent 7/10 of his money. (He has 3/10units left + 3/10*576, since he initially had $576 more than Suhailah)

Thanks!

isn't "at first" $6698? or maybe i misunderstood the qn.

Maybe the question is asking how much EACH of them had at first?

hmm... i drew a model but i ended up solving by algebra.. so sorry.. i hope someone has a non-algebra solution for u.

You need to make sure the number of units are the same for Nick and Osman after they spent the money. For Nick, he has 2/5 left.....means 2 units left whereas Osman has 5/7, 5 units left. You can't compare it when they are not the same number of units. So the best way is to have 10units left for both. Nick 10/25 and Osman 10/14.

Nick = 25u * $159

Nick $3975 and Osman $2723

Thanks so much!

Osman's can be calculated by 14u + $355 + (4* $35.50) where u = $159. Or $6698 - $3975