Thank u! That's really helpful 😊

(a) Letter "I" (b) 1275

Friday has 6 letters so will have a multiple of 6. It happens to be on letter R. 121 = 120+1 and 120 is a multiply of 6.

Number "1" is not under letter "F" If thinking of multiples of 6 121 must be subtracted with first 4 numbers, then divided by 6, will get remainder 3. 121-4=117 117/6= 19 R3

question（a）now i understand need to help question（b）tks

As the picture, Q(b) is below

1+50=51 2+49=51 3+48=51 4+47=51 . . . 25+26=51 So 25x51= 1275

There is a formula for summation of numbers, but I would caution care to be taken when using this formula to ensure the user understands the concept behind the formula. 1/2 × (1 + 50) × 50 = 51 × 25 = 1275

n(n+1)/2 👍🏻👍🏻

Thanks all！

Thanks !!

No problem ! Hope u can understand..

So the only way is algebra ? If students are not good with algebra ，how 😕

At first my girl refused to learn but I forced her cos I think most questions need to have equations somehow. Now, she loves it and can solve sums easily.. Let your child make equations out of model drawings. Refer to my model drawings :- Blue is 3x = 4◻️ + 1 and Red is 2x = 3◻️-1. I use ◻️ in equations instead of units to illustrate. Somehow she can see better.. She is in P5 now and can solve P6 (FDPR) questions.

The total number of pens in both scenarios were the same. Scenario One B : R : total 4 : 3 : 7 20:15:35 Scenario Two B : R : total 3 : 2 : 5 21:14:35 In scenario one, blue was 20 units while in scenario two blue was 21 units. Remember that the total number of pens in both scenario were the same, so one unit must be one pen. Hence there must had been 21 blue pens and 15 red pens at first.

How can 10children=28divid4=7？tks

40 children divided into 4 groups. Therefore adults also have to divided into 4 groups too 10 children = 7 adults

40 chd = 28 adt, thus 10 chd = 7 adts. Since there are already 10 children, (which is also equal to 7 adults), hence 28-7 = 21 more adults can fit in..

Sorry i still dont understand why 28-7？tks！

10 children = 7 adults A bus can take 28 adults. Therefore 28 - 7 = 21. So 21 more adults can sit in

Because max adult can go in the bus is 28 correct ? Since 10 chd is also equal to 7 adts, hence 21 adt still can go in..

ic ic！ thanks Webdy and Pauline！

I think this question tests the student's ability to recognise which multiplication table do the numbers fall under. 40 children and 28 adults falls under 4 times table. Divide both numbers by 4, and you get 10 children for every 7 adults. Since 10 children are on-board, 40 - 10 = 30 For the space of 30 children, 3 groups of 7 adults, meaning 21 adults can fit on-board.