Yes I got it

Should it b A: (A+B)-B ?

Yes, typo error...

999÷4=remainder 3. So it will be in the third column

Thank u for yr help Jun Hong :-)

T

1000 is a multiple of 4. So 999 comes just before 1000 so it has to be T.

Column T. We decide the column depends the remainder. M=1, A=2,T =3, H=0. 999÷4=249R3. So column T is the answer.

Common question, even at P3! Good to know and understand. :)

Pai say...I'm low educated. I know this may seem easy for u guys but I'm the same or lower level than most P4. Hope u all support me dun laugh at my dumbness ok :p

Don't worry about it. We are here to help.

For such questions, we look at the numbers for a pattern. In the table given, the H column is easiest to work with since the numbers are multiples of 4. We also notice we can add or subtract to get the other numbers on the same row. Next thing to do is ask which multiple of 4 is closest to 999 (1000) and how 999 could be 'related' to a multiple of 4 (how many more than or less than?)

Yadana Htunwai

If the distance travelled by the second train is 1 unit, distance travelled by the first train would be 5units + 100km. 1units+5units+100km=400km 6 units = 300km 1 unit = 50km Distance covered by first train= 5x50km+100km = 350km Speed of train= 350km/5h = 70km/h

Why equate the units to 400km? Can explain.

At 2 pm, an hour later, the distance between them INCREASES BY: 70km+70km-20km=120km Distance between two trains = 400km + 120km = 520km.

The trains are travellig in opposite directions. So the total distance travelled by both trains is equals to the distance between the two trains.

Don't quite understand this.

Is there another way of seeing?

Thanks Shu Zhong Shu Hao & Vera !

Solution for (a)

Algebraic method: Let v and v+20 be the speeds of the trains. The distances travelled are v and 5(v+20) respectively. The total distance travelled is 400 km. v + 5(v+20) = 400 Solving the equation, v = 50 The speed of the train heading east is 70 km/h. At 2 pm, distance between the trains = 400 + 50 + 70 = 520 km

This problem is more appropriate for secondary school.

This one has been answered before. If you look through the photos for this FB group, u should be able to see this photo and the solution.

Thanks

Post was on 9 May. I copied and pasting solution here: The challenge in this question is finding the area of the two shaded triangles. Each shaded triangle = area big triangle - area SXT = half area of square - 1/2x10x6 = 20. Total area of two shaded triangle is 40. The shaded area in the square TMNO is more straightforward.

Vei Li, where is the big Triangle? Why half area of sq - area SXT? Y is in mid-pt?

The vertices of big triangle are S, T and the unnamed point between P and Y. It is half of the area of the square because that triangle's height and base are also the length and breadth of the square.

Whether or not Y is the midpoint is not significant. It is there as part of info for the height of triangle SXT.

Vei Li, ok I got it. Thank you very much.