Relax... don't get frustrated. Come next year, you can say goodbye to all your models liao 😄

Oh man.. Are the kids even taught these kinds of strategies in school?

Oh, thanks Raymond! Unfortunately, I have no. 2 and 3 sitting for their PSLE in 2 and 4 years, respectively! 😂 maybe I'll be a pro by then?!

Oops! Didn't realise I'm talking to a parent 😄

And yes, you'll probably be a Math Coach for PSLE by then... 😉

Haha! Yes indeed.. With all this revision going on, it sure feels like I'm the one sitting for the PSLE! 😅

Sorry. Overlooked your 1st question. Erm... for that, I'm sure there're enough MOE specialists / teachers here to answer your query... That's beyond my pay scale 😄

Let the numbers be x and x+2 x(x+2) = 528 x^2 + 2x - 528 =0 (x-22)(x+24) = 0 x= 22 OR x=-24 Hence, the numbers are 22 and 24.

Also, it can be -24 and -22. :)

Just square root 528 and you will get a number to start with.

20sq is 400 and 30sq is 900. So the 2 numbers shld be between 20 and 30. Given that last digit is 8, so it shld be either 22x24 or 26x28.

Even if u use x and x+2 and form a quadratic equation, u still need to divide 528.

529 = 23 * 23, so 22 * 24 = 528

Im assuming to solve this without a calculator. How will you know sq root of 529 is 23 in the first place

Lol trial and error..... XD

Agree trial and error can. But u still need a starting point right.

why can't -22 or -24 be used since they satisfy the equation as well?

Also can

Length = 60 -1-1=58cm (deduct 1 cube each from left and right side) Breadth = 12-1-1=10cm (deduct 1 cube each from both sides) Height = 30-1= 29cm (deduct 1 cube from bottom side only as the box is open)

nice drawing!

Thank