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Sivasothy Nanthagopal

Asked 8 years ago

SG Primary 6 Measurement

Replies 3

Soo Vei Li

The shaded area can be found by subtracting the of the two unshaded circles from the big circle.

5 years ago

Soo Vei Li

If you take a pencil and trace the outline of the shaded part, you will see that the perimeter is the sum of the circumference of the big circle and the 2 smaller circles.

5 years ago

Irene Ong

5 years ago

Sivasothy Nanthagopal

Asked 8 years ago

SG Primary 6 Measurement

Replies 1

Irene Ong

5 years ago

Mavis Low

Asked 8 years ago

SG Primary 6 Measurement

P6 qns again. Appreciate your help. Thanks!

Replies 1

Soo Vei Li

These questions hv been posted and solved before (I think 3 times for the area one). If u scroll thru the photos, you might be able to see them.

5 years ago

Mavis Low

Asked 8 years ago

SG Primary 6 Measurement

Replies 6

Irene Ong

http://geniebookapp.com/public_question/39327a/bO10OZV4eOZJCGh4h1s9o8Qt6iR12zBT

5 years ago

Mavis Low

Wow.. Thanks!

5 years ago

Soo Vei Li

Here's a repost from 9 May: The challenge in this question is finding the area of the two shaded triangles. Each shaded triangle = area big triangle - area SXT = half area of square - 1/2x10x6 = 20. Total area of two shaded triangle is 40. The shaded area in the square TMNO is more straightforward.

5 years ago

Soo Vei Li

And there were some follow-up questions from the solution given...

5 years ago

Mavis Low

Thanks Vei Li! Although I find it hard to assume that the point bet P and Y, to point X to point T, is a straight line. A piece of info like that should be stated in the question? And not left to us to assume?

5 years ago