iMath | Community

Shaw Feng

Asked 9 years ago

SG Primary 6 Fractions

Need your help to solve this problem sum. Thanks.

Replies 3

Mike Tan

The question looks fuzzy!!!

6 years ago

Yeo See Yeong

((1u+73) + (4u-38)) / 2 = 180. Hence u = 65. Hence, at first, A had 65+73 = 138 and C had 4x65 -38 = 222

6 years ago

Caleb Tey

6 years ago

Rosalind Teo

Asked 9 years ago

SG Primary 3 Number and Algebra

Is there another way to solve this besides using guess&check and algebra?I am able to get the answer using algebra though.If using guess&check, how do we present the solution in the simplest form.Appreciate your advise.Thank you

Replies 9

Ging Yang Choo

24 * 4 = 96 assume all vehicles are cars 4 - 2 = 2 extra wheels per vehicle 96 - 66 = 30 total number of extra wheels 30 / 2 = 15 is number of motorcycles 24 - 15 = 9 number of cars 15 - 9 = 6 more motorcycles than cars

6 years ago

Maggie Lukes

Assume all the vehicles are cars. This means there would be 24 x 4 = 96 wheels. 96-66=30 too many wheels for the questions. The difference in the number of wheels between a car and motorcycle is 4-2=2. So the number of motorcycles is 30/2 = 15, and the number of cars is 24-15 = 9. (Check: 9x4=36, 15x2=30, 36+30=66). So there are 6 more motorcycles than cars.

6 years ago

Rosalind Teo

Thank you all so very much for the solutions. Much appreciated!

6 years ago

Mike Tan

Eliminate 2 wheels from every vehicle and you eliminate all the wheels of the motorcycles and cars are left with only 2 wheels each, hence in the third line, you divide 18 (remaining wheels) by 2 (wheels left on each car): 24 x 2 = 48 66 - 48 = 18 18 / 2 = 9 (cars) 24 - 9 = 15 (motorcycles) 15 - 9 = 6 (Answer)

6 years ago