46-(9x2)= 28 28/2=14 (length) vol = 14x9x7 = 882cubic cm

Hi. Refer to the image below for the volume of the cuboid. :)

Thank you so much.I can understand so clearly. nice explanation Shaoyang Brandon

One layer will contain (18/3) × (9/3) = 6 × 3 = 18 cubes No. Of latter's =126/18 = 7 layers So height= 7 x 3 = 21cm

7658-645-645 =

Thank you

Working is simple. But need to understand the thinking.

For p3 wor, can have the "U"?

A similar problem was posted a few days ago that you may want to look at as well. Solution below... By reasoning: After groups of 45 beads have been formed, there are 33 left. To make the groups of 53 beads, we use the 33 extra to add 8 beads to the original groups of 45. In addition to the 33 extra beads, we also need 39 more. That means the number of beads needed to add on to the groups of 45 = 33+39 = 72. Since we are adding 8 beads per container, number of containers = 72/8 = 9.

Faint... Thanks everyone!

Excess + shortage question.

×6 6 12 18 24 30 36 42 48 54 +6 12 18 24 30 36 42 48 54 60 ×8 8 16 24 32 40 48 56 64 72 -12 - 4 12 20 28 36 44 52 60 For a p3 child, you can use this method. 1st scenario is each child gets 6 choco bars, then it is multiples of 6 and add the 6 extra ones. 2nd scenario is each child gets 8 choco bars, there will be a shortage of 12 bars, you subtract from the multiples of 8. At the 9th column, you see '60' repeated twice. This means there are a total of 60 choco bars. Since it appeared on the 9th column, there are 9 children. It is excess / shortage Q but if the child is yet exposed to units, this method is clear. Another way is Guess and Check. But tedious. Hope it helps.

Not sure if this explanation is easier to understand. A) 6 choc each = balance 6 8 choc each = short of 12 Therefore to give 2 more chocolates to each student, teacher needs 12+6=18 more chocolates 18 chocolates / 2 each = 9 students b) (9x6)+6 = 60 chocolates

My hubby did this

Hi, Carol. Refer to the image below for the solution. :)

Thanks:)