SG chevron_right Primary 6 chevron_right Geometry
Please help. Thanks
(a) 1/3(50)(20)(54) =18000cm cube (b) 1 min in A = (1800)/(60)(10)) =3cm I min in B = (1800)/(50)(20) =1.8cm 1/3(54)= 18cm (18)/(3-1.80) = 15min They will be at the same height 15 minutes later.
Here you go
SG chevron_right Grade: N/A chevron_right Strand: N/A
Can show the whole question? Thanks.
Perimeter =2(3.14)(10)+2(3.14)(5)+2(10) =114.2cm Area =(3.14)(10)square - 4(5(10)-1/4(3.14)(5)square) =192.5cm square
SG chevron_right Primary 5 chevron_right Geometry
Pls help
Volume(cube)=40cm*40cm*40cm=64000cm^3 Volume(cuboid)=20cm*40cm*80cm=64000cm^3 TotalVolume=64000cm^3+64000cm^3=128000cm^3
SG chevron_right Primary 6 chevron_right Number and Algebra
Help
14-2=12 12*4=48 48+20=68 68*(3/2)=102