Here you go

Thank yoi

Just have to get familiar with the notation.

You need to find the highest commonf factor between 48 and 80. 48 --> 1, 2, 3, 4, 6, 8, 12, 24, 48. 80 --> 1, 2, 4, 8, 10, 20, 40, 80 So the hcf is 8cm.

Huh

Sorry i dont quite understand can explain

You need to cut each string into pieces of equal length with no remainders. Step 1 : So first try to find all the possible lengths for the 48cm string than the 80cm string.

Then ...

Step 2: To do that you need to find all the numbers that can be divided equally from 48 - 1,2,3,4,6,8,12,24,48.

Step 3: Then do the same for 80 - 1,2,4,8,10,20,40,80

Step 4 : Compare both sets and find the biggest number in which case 8

What is the awnser of the question i dont understand your explanation

So you can cut the 48cm string into 6 pieces of 8cm each. And the 80cm string into 10 pieces of 8 cm each.

8cm

Sorry can u work ot out for me

Can i check in the apove explanation which steps ( 1,2,3,4) do you not understand? I will try explain in detail from there.

Hmm, Raseena, you missed out the factors 5 and 16 for 80, and factors 3 and 16 for 48, which means they have common factor of 16.

Oh yes, thx for checking that!

The dash on the sides of the trapezium indicate that itts equal. Hence this is an isocles trapezium. Opposite angles of an isocles trapezium are supplementary (i.e. add up to 180°) So 5x = 180°; x= 180°÷5 = 36°

Here you go

Thanks!