Hi, you read the question wrongly. th number of boys is 1/3 of children, not of participants.
5 years ago
Johny Quek
Hi, you read the question wrongly. th number of boys is 1/3 of children, not of participants.
5 years ago
Lynn Liew
Thank you
5 years ago
Mandy
Asked 5 years ago
SG
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Primary 6
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Number and Algebra
Please help me!!
Replies
1
Siti
Working
5 years ago
Mandy
Asked 5 years ago
SG
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Primary 6
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Number and Algebra
Please help me!
Replies
6
Kelvin Tan YC
Good..
You figured out J:L = 20:25. After L gave J 110 comics, J:L = 3:1.
Note that this is internal transfer, so total (J+L) is unchanged
Toral number of units before the transfer = 20 + 25 = 45. After the transfer, total number of units = 3 +1 = 4
Equate them, lcm of 4 and 45 is 180
J:L = 20:25
= 80:100
J:L = 3:1
= 135:45
You see J will have 55 more units than before and L will have 55 units less than before
55u= 110
1u = 2
T:J = 17:20
= 68:80
You have to factor those ratio bevause you did that to units for Julie earlier
100u - 68u = 32u
32u = 64
Ans: 64
68u + 80u + 100u = 248u
248u = 496
Ans: 496
5 years ago
Kelvin Tan YC
T:J:L= 17:20:25
J:L = 20:25
J:L = 3:1 (if L gave 110 comics to J)
This is internal transfer, so J+L before and after the transfer remains the same
Total number of units before the transfer= 45
Totel number of units after the transfer = 4
Equate them, lcm of 4 and 45 is 180
J:L = 20:25
= 80:100
J:L = 3:1
= 135:45
You notice that J will have 55 units more than before and L will have 55 units less than before if the transfer takes place
55u = 110
1u = 2
T:J = 17:20
= 68:80
100u - 68u = 32u
32u = 64
Ans: 64
68u + 80u + 100u = 248u
248u = 496
Ans: 496