Gelene Ong
Asked 5 years ago

SG chevron_right Secondary 2 chevron_right Add Math: Algebra

not sure how to solve

Replies 1
Dila88

(a) Replace value of n = 1, 2, 3, and 4 The result of sequence you will find is -1, 5, 15, 29. (b) Comparing both sequence, you will noticed that is additional +4 in each term of sequence. Then, for the new n-th term now become (2n^2 - 3) + 4 = 2n^2 + 1.

5 years ago

iMath
Asked 5 years ago

SG chevron_right Primary 6 chevron_right Number and Algebra

Please help. Thanks

Replies 3
Kelvin Tan YC

Part 1

5 years ago
Kelvin Tan YC

Part 2

5 years ago
Kelvin Tan YC

Part 3

5 years ago

emmac
Asked 5 years ago

SG chevron_right Primary 5 chevron_right Number and Algebra

Replies 4
happy

No.of erasers in extra box= 7×12. No. of boxes originally= 84÷2 +8÷2= 46 No. of eraser= 46×9= 414

5 years ago
emmac

Hi happy, thanks so much for helping! I don’t understand the second sentence, why 84 / 2 + 8 / 2? Can you explain thank you!

5 years ago
emmac

Hi happy, thanks so much for helping! I don’t understand the second sentence, why 84 / 2 + 8 / 2? Can you explain thank you!

5 years ago
happy

Cause each packet has a decrease in 2 erasers -that were later boxed up, you divide the no. of erasers taken out of the original box and which is 84+8 and divide it by 2 to find the number of boxes

5 years ago
emmac

I see! The diff of 2 (each) actually indicates how many boxes (groups) there are! So total (84+8) divide by each (2)will give groups (boxes). Wow thanks for clearing it up!

5 years ago

iMath
Asked 5 years ago

SG chevron_right Primary 6 chevron_right Geometry

Please help. Thanks

Replies 1
Soo Vei Li

Solution

5 years ago

iMath
Asked 5 years ago

SG chevron_right Primary 6 chevron_right Geometry

Please help. Thanks

Replies 1
Soo Vei Li

Solution

5 years ago

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