MJ Bhatt
Asked 9 years ago

SG chevron_right chevron_right

https://www.facebook.com/IloveMathematics91/photos/a.601527433214764.1073741825.601278736572967/932253810142123/?type=1&theater

Replies 0

Dawn Jacobs
Asked 9 years ago

SG chevron_right Primary 4 chevron_right Number and Algebra

How do we solve this problem using bar models?Apples are sold at 3 for $2 at Busy Mart. At Big Foods, the same apples are sold at 5 for $2. Kissim buys 15 apples from Big Foods instead of Busy Mart. How much does he save?

Replies 5
Dawn Jacobs

Thank you very much! We are trying to learn the bar model ... Still trying to get a handle on it.

5 years ago
Jeremy Hannay

Sorry for the finger drawing. But I'm sure you get the idea. Haha.

5 years ago
Jeremy Hannay

It's tricky at first - but once you do it a few times you start to see problems in bars. Haha.

5 years ago
Jeremy Hannay

If you haven't seen these already, they might be helpful. Scroll down for bar modelling http://www.threebridgesprimary.co.uk/page/singapore-maths/88

5 years ago
Dawn Jacobs

Thank you... I could use all the help I can get... Will check it out.

5 years ago

Grace Ong
Asked 9 years ago

SG chevron_right Primary 5 chevron_right Fractions

Replies 4
Adrian Ng

5 years ago
Vera Koh

5 years ago
Pieter Cronje

5 years ago
Yueh Mei Liu

5 years ago

Allison Chin
Asked 9 years ago

SG chevron_right Primary 6 chevron_right Number and Algebra

Pls help....

Replies 6
Adrian Ng

5 years ago
Allison Chin

Thanks <3

5 years ago
Yueh Mei Liu

5 years ago
Allison Chin

Thanks :)

5 years ago
Thit Mon Mon Win

5 years ago
Allison Chin

Thanks😃

5 years ago

Clare Means Bright
Asked 9 years ago

SG chevron_right Primary 5 chevron_right Number and Algebra

Help needed... Thanks in advance!

Replies 10
Bertrand Chew

therefore, orginal 4 duck parts + 5 chicken parts=78. 3 duck parts and 2 chicken parts is 48(left). Hence sold was 1 duck part with 3 chicken parts=30. To make it 3 duck parts, we have 3 duck parts and 9 chicken parts=90. Hence 7 chicken parts =32, once chicken part is 4. There were 5 chicken parts=20? hope i get it right. otherwise can someone enlightened me how to solve this..came from the old algebra school.

5 years ago
Thit Mon Mon Win

D+C= 78 ------1 3/4D (1:3) + 2/5C (2:3)= 48 So 15D+ 12C= 960 ------2 --1 - -----2 = 7C = 210 Chicken = 30

5 years ago
Lynette Lim-Juan

I have 30 as the answer too.

5 years ago
Adrian Ng

5 years ago
Mavis Low

Both the solutions presented seem like they are using simultaneous equations to solve.. Something only taught in Sec 2. Are our primary school students expected to know this method? Or can the question be solved using the model method?

5 years ago
Clare Means Bright

Mavis Low, if u try to recall, the kids were alrdy exposed to such concept when they were in P2. Example ☀️+⭐️=30 4☀️+⭐️= 60 Find the value of ☀️ and ⭐️

5 years ago
Adrian Ng

5 years ago
Adrian Ng

5 years ago
Soo Vei Li

Here's the model method without the abstract algebraic representation but which primary school students can understand because it is more visual. This is one way to foster pre-algebraic thinking in younger students.

5 years ago
Kai Meng

Colours are used only to avoid using curly brackets.

5 years ago

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