Lee Yuet Meng
Asked 9 years ago

SG chevron_right Primary 4 chevron_right Number and Algebra

Anyone can help? Thanks in advance.

Replies 5

Choy Ban Heng

I used the same method as the one below. Hope it helps

5 years ago
Vera Koh

5 years ago
Lee Yuet Meng

Thanks, Choy Ban Heng!

5 years ago
Lee Yuet Meng

Thank you, Vera Koh

5 years ago
Adrian Ng

5 years ago

Ow Yong
Asked 9 years ago

SG chevron_right chevron_right

Thanks for adding me

Replies 0

Michael Tan
Asked 9 years ago

SG chevron_right Primary 5 chevron_right Measurement

Hi, Anyone can solve??? Thanks!

Replies 12

Pieter Cronje

5 years ago
Thit Mon Mon Win

$0.50 = 1 u $0.20 = 1 u + 6 ($0.50 x 1 u) - $0.20( 1 u +6) = $ 2.70 u = 13 13 x 0.50 = 6.50

5 years ago
Thit Mon Mon Win

$0.50 = 1 u $0.20 = 1 u + 6 ($0.50 x 1 u) - $0.20( 1 u +6) = $ 2.70 u = 13 a) 13 x 0.5 = $6.50 b) 13+6= 19

5 years ago
Michael Tan

Thanks All :)

5 years ago
Vera Koh

sorry for the "wordy" explanation. thought it may be clearer with the words.

5 years ago
Michael Tan

Thank U :)

5 years ago
Mohi Uddin Ahmed

Handwriting looks great too!

5 years ago
Choy Ban Heng

Here's another solution:

5 years ago
Vera Koh

Choy Ban Heng, $1.20 for Meimei is only 4x 30¢.. (even though it is 6x 20¢ coins for Sarah). so, number of coins Meimei had should be 9 + 4 = 13. this is a good model to see the 9x 30, but may result in careless mistake when comparing the $1.20 part cos the "u" for 20 is not the same length as the "u" for 30. :)

5 years ago
Choy Ban Heng

Here's the updated one. Thank you Vera Koh for pointing out the careless mistake. I think the problem could have been overcome if I have checked my typing and calculations.

5 years ago
Michael Tan

Thank you for your Diagram method :)

5 years ago
Adrian Ng

5 years ago

Winnie Win
Asked 9 years ago

SG chevron_right Primary 6 chevron_right Number and Algebra

Replies 3

Pieter Cronje

You can see patches in the drawing ... Little humps....Count the blotches in the shaded area.( about 38) Then gues about the same space that is equal to the non shaded and count the blotches...(about 9) 38/(38+9)=0.80 this x 100 gives about 80%

5 years ago
Winnie Win

Oh... Still must count the blotches? Is 75% acceptable?

5 years ago
Pieter Cronje

The question was "estimate". I think they just want you to make a guess based on some relative basis...75 will also do...

5 years ago

Winnie Win
Asked 9 years ago

SG chevron_right Primary 4 chevron_right Fractions

Replies 5

Yueh Mei Liu

5 years ago
Winnie Win

Thank you, Yueh Mei!

5 years ago
Pieter Cronje

5 years ago
Winnie Win

Thank you, Pieter Cronje!

5 years ago
Adrian Ng

5 years ago