Hi Sh Lim, why the answer isn't 54?

The tarts must be devisable by 3 and total must be increased by 10 and then be devisable by 4. So 51 tarts is devisable by 3 but 61 not. 54 is devisable by 3. 64 is devisable by 4! So voila! 54 tarts

Answer 54 is marked wrong. The answer given by teacher is 66.

the teacher is wrong

I think so too, Mike Tan. 😑

The teacher is not correct. Lowest is 54 66 is another possibility

Sorry, shd b 54, not 66. I was in a rush juz now.

Ok. So the teacher is definitely wrong. Thanks, everybody.

For 54 tarts in 4 per packet, don't we have short of 2? Saying short of 10 is confusing me.

GC Lau yeah the way they wrote the question really confusing.

Assuming that the answer is indeed 66. This would mean that there are 66 / 3 = 22 packets from the first case. So if there are 22 packets and she packs 4 into each of them, she would need a total of 22 x 4 = 88 tarts. Which means that she should be short of 88 - 66 = 22 tarts instead of 10. If this is an excess and shortage question where the number of groups is NOT fixed, then there should be ONLY be remainders or fully divisible, no shortage. The same reasoning can be applied for when the number of tarts is 54: 54 / 3 = 18 packets (1st case) but 64 / 4 = 16 packets (2nd case) Doesn't tally, something seems wrong.

Kevin Hzh, it is not stated or implied in the question that the number of packets is a fixed number.

Agreed, it's not stated or implied over here. But issnt it funny if he has 18 packets in the first case but only 16 packets in the other?

Because Miss Zahirah has not decided how many packets she should packed? She is just trying to pack all in so that there is no wastage? But she did not study her math well in primary school and therefore does not know her multiples well? 😜

Both 54 and 66 satisfy both conditions but only 54 satisfies the 3rd condition, i.e. minimum number of tarts.

No 2

options 1,3,4 can all be tessellated.

Can u elaborate. Thank u.

Thanks

welcome! 😊

What a great word - tessellated!

Yeah, sometime one have to understand the definition of the word before solving the math problem

haha Primary sch math only need to know "tessellation"... Sec sch need to know more! esp in A math.... Binomial, sine, cosine, secant etc

Can i know which level?

P6

Should be P5. :-)

Oh P6...4m qn?

Yes 4m qn

Answer is 214

Thanks you. Suddenly so clear now 😊

Have to make the cakes units the same

Qn stated all cakes were sold, so got to make the cakes to have equal units.

Hi BA Poh Ann, how to use method one to explain the 15 units?

' 4 pies & 1 cake' equal to '16 pies & 4 cake' for equal comparison. Use 16 pies and minus off the 1 pie from the 2nd equation, will get the 15 unit

Not sure if it is correct, but I get 214.

214 is the total. :)

thanks BA Poh Ann. I didn't check prior solutions and not very confident of my answer.

Ans:$62?

Thank u guys.