Janu Rafiq
Asked 8 years ago

SG chevron_right Primary 6 chevron_right Number and Algebra

Pls help

Replies 3

Chia-Chan Bk

5 years ago
Janu Rafiq

Thanks for the Ana

5 years ago
Janu Rafiq

Sry ans

5 years ago

Charlene Danzeldarielledelia Eric
Asked 8 years ago

SG chevron_right Primary 3 chevron_right Number and Algebra

P3 maths. Pls help.Eric See Toh

Replies 7

Soo Vei Li

You can work backwards... Start by drawing models to represent the 'after' situation: S has 1 unit and Y has 7 units. Then complete the bars to show the 'before' situation using the info given (92 given away & 8 lost). You can refer to a similar problem solved earlier tonight https://www.facebook.com/photo.php?fbid=461246857387569&set=gm.495101037313224&type=1&theater

5 years ago
Joe Neitham

Is this correct?

5 years ago
Izam Marwasi

End Yvonne 7u Sheryn u Dif-6u Dif in lost/given away= 92-8=84 6u=84 u= 14 At first Y-7u+8 E-u+92 7u+8+u+92= 8u+100 == 8x14 + 100= 212

5 years ago
Soo Vei Li

Joe Neitham, your model is not fully correct because you did not get the the two girls having same number at the start. But you somehow got the correct answer because of a mistake in solving the algebraic equation. I've shown it in the photo.

5 years ago
Joe Neitham

Thanks Vei Li Soo for pointing that out :-) So is the answer 106 the number of stickers each of them have at first?

5 years ago
Soo Vei Li

Yes, they each have 106 at first.

5 years ago
Xavier Sng

I like Izam Marwasi's method as it utilizes the concept of difference to arrive at the answer quickly.

5 years ago

Irene Kong
Asked 8 years ago

SG chevron_right Primary 6 chevron_right Measurement

Pls help.

Replies 2

Yeo See Yeong

Volume of Clay = 48x30x5 = 7200cm^3. volume of cube = 1000 cm^3. (a) 7200/1000 = 7.2. Therefore, maximum cubes can be formed = 7 (b) Volume of clay left = 200cm^3

5 years ago
Irene Kong

Thank yeo see yeong.

5 years ago

Vivian Ang
Asked 8 years ago

SG chevron_right Primary 6 chevron_right Number and Algebra

Help please.thks

Replies 2

Xavier Sng

(a) 100 min before 1pm is 11.20am. (b) speed of slower printer = (70 times 6) divided by (100min - 70min) = 14 copies of newsletter per min Each machine printed 14 times 100 = 1400 newsletters Total number of copies printed by the two machines is thus 2800.

5 years ago
Caleb Tey

5 years ago

Vivian Ang
Asked 8 years ago

SG chevron_right Primary 6 chevron_right Measurement

Help please!thks

Replies 3

Richard Gavina

Perimeter of the large semicircle, add the perimeter of a small circle, lastly twice the length of a line..

5 years ago
Richard Gavina

Area Area of large semicircle + Area of the square - area of a small circle.

5 years ago
Siti Julaeha

5 years ago