Thank you Adrian

Let c be no of containers. No of beads = 45c + 33 = 53c - 39 33 + 39 = 53c - 45c 72 = 8c C = 72/8 = 9

Many thanks

Is this not considered algebra? P4 can't use algebra rite?

Add: 33 and 39 = 72 53 - 45 = 8 72/8 = 9 This is the formula for such qn: (39 + 33 ) /(53 - 45) = 72/8 = 9

We came across this question too. Algebra method will just frustrate everyone. The above formula works for all such qn and I made my son memorise it... (though can't make much sense of it ) :p

https://youtu.be/UwvWEu2j7tM Similar question. For some visual explanation.

Hi Cindy ..u have other way to solve

No I dun, but cos my son's teacher rejected one algebra working saying they are not taught yet.

I respectfully disagree. If a student is ready for algebra, he should be taught algebra.

Many thanks Vanessa

Welcome

I'm going thru your video..much appreciated and many thanks again.

Thank you Vera n Joscelin 😉

Guess and check

8 $2 dollars and 14 $5 dollars, using guess and check method.

14 $5 notes

Hope this is the working

Can also use the assumption method : Let assume all are $5-notes, 22 x $5 = $110 $110 - $86 = $24 Difference between a $5-note and a $2-note = $3 Thus, $24 ÷ $3 = 8 Since there are 8 pcs of $2-notes, 22 - 8 = 14 pcs of $5-notes

My gal and boy love to help ;)

Yes. This is guess and check.

Alternative assumption working. Can also use the assumption method : Let assume all are $2-notes, 22 x $2 = $44 $86 - $44 = $42 Difference between a $5-note and a $2-note = $3 Thus, $42 ÷ $3 = 14 Since there are 14 pcs of $5-notes, 22 - 14 = 8 pcs of $2-notes