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Choice 1. The clue is to look at the figure and see whether it can form back to form a rectangle or square (besides other basic shapes) because a rectangle or square can tessellate.

I wld think that (3) wld be correct since b can be tessellated too

Trina Chang is right. Answer is (3)

Oh yes. My bad. Sorry. Didn't see that it's equal in size.

My apologies , din notice tt..👍

Thanks all

B and D.

36 ＝ 1×36 2×18 3×12 4×9 6×6 Sum ＝ 1+2+3+4+6+9+12+18+36 ＝ 91

I may bevwrong but i think .... 36 = 2 × 2 × 3 ×3 So sum = 2+2+3+3 = 10

Yes it shld be the sum of 1,2,3,4,6,9,12,18 & 36 = 91

Thank you all

Those are the prime factors.

Should it be 91 if you add up?

sry my bad 😅

Well continue to contribute. Not only for P6 but also for all othwr levels. As the model get more complicated, i this old man can never catch up.

Thanks. I thought half of total of no of flowers is 48/2=24. And D is 14 so the difference 24-14=10 ie the answer.

Welcome:) Yeah trick is D becomes half of the new total which means the other two will now become half also.

A has 40% B has 40% + 40 B has 4 times as much as C. C has 10% + 10. Total = 40% + 40% + 40 + 10% + 10 = 90% + 50. So total 500 sweets and C has 50+10 = 60. So A has 100 and B has 140 and C has 60 sweets after A n B gave some sweets to the brother. No of sweets given to brother = 500 - 100 - 140 - 60 = 200.

Robert Yeo..thank you very much

Second problem. C:D = 2:3 E:D = 6:7 C:D:E = 14:21:18 Draw 14 boxes 21 boxes 18 boxes. 7:9 donated. = 64 7+9 = 16 So each box has 4 candies. Total 14+21+18 = 53 boxes.. So 53 × 4 = 212 candies. Oops ..... did not answer the q. No of candies after donation = 212-64 = 148

Robert Yeo..thank you very much

This is actually a P6 syllabus question

Hariani Salleh..thank you very much

Not at all

:)