A+C=$585----> eqn 1 A+B=$225-----> eqn 2 eqn 1 minus eqn 2 C-B-->> $585-$225= $360 C-> 4u B-> 1u 4u-1u-> 3u-> $360 1u-> $120 B=$120 A+B=$225 A + $120=$225 A=$105(answer)

Thanks!!!! Izam! !!

A) 1500-1420=80 B) 2240-1500=740 1420-740=680

Thanks michelle 😊

welcome

Appreciate your clear explanation, Hariani. Thanks!

Thanks Sheryl!

Not at all

Tks for your explanation!

B = 4. Take 2855 + 2_86 and you can slowly work out the value of B.

When all else fails, try all the digits from 1 - 9 lol. Anyway answer is 4.

B= 4

Thanks Huixian and Hammy😘😘

Thanks Cheryl😘

Welcome :)

4. The '1' in the ones place cannot allow 6to be deducted so u must borrow 10 from the tens place. 8+5 in the tens place =13 which ends with 3 which means b must be 3+1 (need to add 1 cos this 1 is borrowed by ones place in order to be subtracted by 6)

Thanks Trina😘

B=4

Thanks Angelina 😘

4

Just reverse the subtraction. No analysis needed.

Thanks Cheryl and Kai Meng

*4

4

Thanks Nalini

4

B is 4

Starting from left, 2 + 2 = 4, so a thousand must have been borrowed to the right. 13 - 8 = 5. However, looking to the next column on the right, a hundred must have been borrowed to minus 8. So, B = 4 in the hundreds column. Testing this hypothesis by putting B = 4 in the tens column, 14 - 8 = 6. Our hypothesis is confirmed when we look at the ones column requiring a loan of a ten, thus making the tens total a 5. Also, in the ones column, 11 - 6 = 5.

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