57 x 4 = 228

This looks more like a P4 question than P3.

Goes after the concept of squares having 4 equal sides. 57 x 4 = 228

Thank you

57×4=228

Thank you, would you please explain in steps

Hope this helps.

Answer 8:3

Case 1 K:L 14:28 Kim left 182 Case 2 K:L 28:14 Kim left 56 Case 1-> 14:28-> 1:2 Case 2-> 28:14-> 4:2 Lin ratio is the same for both cases as Lin is left with zero in both cases. Kim -> 4u-1u=3u=182-56=126. u= 42 Case 1 Kim-> 1u+182= 226 Lin-> 2u= 84 Kim:Lin 226:84 8:3 (answer)

There are FOUR hints to this question. HINT 1: 3/8 of her remaining money = 3/10 of total money at first. HINT 2: So, it means 5/8 of her remaining money = 5/10 of total money at first. HINT 3: Therefore, her remaining money = 8/10 of total money at first. ***HINT 4: Where did the 2/10 of total money at first go to? Her mother ($800). ***2/10 of total money at first = $800. So, total money at first = $800 x 5 = :)

I got it. Thanks.

Q2. Find lowest common multiple and number of packets of pins. Blue: 8, 16, 24 Red: 6, 12, 18, 24 For each set of 24 blue and 24 red, there is a total of 7 packets. 100 / 2 = 50 50 / 7 = 7 R 1 7 x 7 = 49 At most, she could buy 49 packets.

Q3a. 75 / 5 = 15 (ie. 15 more papayas per unit) 285 - 15 = 270 2u: 270 1u: 270 / 2 = 135 135 + 15 = 150 150 x 4 = 600 papayas sold b. Total papayas sold = 600 Total coconuts sold = 135 x 3 = 405 Total fruits sold = 600 + 405 = 1005 Fraction of fruits sold which are coconuts = 405/1005 = 81/201 = 27/67

I got a different answer, though. Let's compare the workings. :)

And the solution. :)

For part (a)

The 7 packets...is it calculated from 3 packets of blue pins and 4 packets of red pins?

Yes it is.

I misinterpreted the part b question, amended now.

Jason Oon No worries. :)