Wong Soo Fei
Asked 9 years ago

SG chevron_right chevron_right

Hope someone can help me with this P5 math

Replies 5
Raymond Ng

6 years ago
Wong Soo Fei

Thank you.

6 years ago
Shaoyang Brandon

Hi! Refer to the 2 images below for an explanation. :)

6 years ago
Shaoyang Brandon

6 years ago
Wong Soo Fei

Thank you shaoyang

6 years ago

Izam Marwasi
Asked 9 years ago

SG chevron_right chevron_right

Is there a better way to solve.. Any model methods..

Replies 6
Izam Marwasi

My solution-> Any other method?

6 years ago
Raymond Ng

Alternatively,

6 years ago
Edlynn Rose

6 years ago
Kai Meng

6 years ago
Izam Marwasi

Thanks. Raymond Ng , Edlynn Rose and Teo Kai Meng for the alternative solutions...

6 years ago
Kai Meng

Welcome!

6 years ago
Kai Meng

Welcome!

6 years ago

Lawrence Zu Xin Wong
Asked 9 years ago

SG chevron_right chevron_right

help needed thx and merry xmas

Replies 4
Kai Meng

Hi, remaining space for additional adults is 1 - (35/42) - (4/36) = (1/18) of bus. Number of additional adults = (1/18)×36 = 2.

6 years ago
Sirisha Suryadevara

6 years ago
Selvakumar Atheeshan Thambirajah

42 children equivalent to 36 adults. So 35 children is equivalent to 30 adults. Already 4 adults there. So, another 2 more adults can be added.

6 years ago
Shaoyang Brandon

Question involves the concept of proportion. So, for every 42 children, there are 36 adults. Or, 7 children for every 6 adults. So, 35 children would be in proportion with 30 adults. Subtract 30 and 4 from 36. It will be at most 2 more adults to be added.

6 years ago

Rachel Lim
Asked 9 years ago

SG chevron_right chevron_right

Please help this P5 question too.

Replies 2
Raymond Ng

6 years ago
Rachel Lim

Thanks

6 years ago

Rachel Lim
Asked 9 years ago

SG chevron_right chevron_right

Please help P5 question.

Replies 4
Raymond Ng

6 years ago
Rachel Lim

Thanks

6 years ago
Edlynn Rose

6 years ago
Shaoyang Brandon

Hi! You can refer to the explanation below. :) 1/3 of remainder ---> 32 coins. (10 cents) 2/3 of remainder ---> 64 coins. (20 cents) remainder ---> 32 x 3 = 96 coins. remainder of coins is 40% of total coins ---> 96 coins. 60% of total coins ---> 96 x 3/2 = 144 coins ($1) Total amount collected ---> 32 x10 cents + 64 x 20 cents + 144 x $1 = $3.20 + $12.80 + $144 = $160 :)

6 years ago

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