one pencil costs $5-$2＝$3.

for every pencil sold, 3 pens are sold. We can let 1 pencil and 3 pens be one unit. so the amount of money collected from 1 unit is $3+$5x3＝$18. Since a total of $630 is collected, the number of units sold is $630/$18 ＝35. Hence, 35 pencils are sold and 105 pens are sold

It is asking for the difference in all sales of pens and pencils ....

amount collected from sale of pens＝105 x $5＝$525 amount collected from sale of pencils＝35x$3＝$105 Difference＝$525-$105＝$420.

for every pencil sold, 3 pens are sold. We can let 1 pencil and 3 pens be one unit. so the amount of money collected from 1 unit is $3+$5x3＝$18. Since a total of $630 is collected, the number of units sold is $630/$18 ＝35.

Thanks Zhong Shu Haoand Chris Rogers ..nice working and explanation !now I see it. Difficult concept for me to grasp!😂

Txs n same to you too.

Thank you n wish all mums a "A Very happy n blesses Mothers Day".

Happy mothers day to all the beautiful mothers who take the pain n passion to coach their kids...

Happy Mother's day to you too!

Happy Mothers' Day to all mums

Thanx! Happy Mother's Day to you!

Not nice to have exams prep during Mother's day.

Take it as bonding time

Happy Mother's Day to all Mums out there ☺

model would be the best :D

Zhong Shu Hao - I actually got stuck with initial part of model. How to equate the sold 3/4 chicken and left 235 chickens and ducks?

wait ah...

Reason that i split C into 4 parts is becos 3/4 of the C is sold...

Thank u all for your help.

A slightly different model. When drawing models, I like to ensure the parts (top and bottom) are equal so there is a basis of comparison. A common mistake that many kids make is that they forget to take away 3/4 of the 160 as well. I have shaded the parts that are taken away.

Lets assume no. of d = x Then no. of c = x+160 Now form the equation (x+160) - 3/4 (x+160) + x = 235 Solve this equation x + 160 - 3/4x - 120 + x = 235 5x/4 + 40 = 235 5x/4 = 195 5x = 780 x = 156 So x is no. of duck Hence no. Of duck is 156

Geraldine Koh..this is P4 or P5 question?

This is actually a p6 questionn

thanks Geraldine Koh.. I was asking my P4 daughter to try and she was clueless :)

Have to use units and parts.

Koh Lay Koon do u mind showing me the workings please? Tks in adv.

is the ans 2595?

I do not have any answer sheet for this paper

Here is my working... Hope P6 students can understand as this "algebraic" method is taught in Sec1...

Koh Lay Koon - is your method same as the one being posted? I am afraid p6 may find algebra way a little difficult to understand. Can u pls share yr solution? Tks.

This is using the units and parts method from onsponge book - p5 level.

Ok thank u both for your help. Greatly appreciated!

Chris Rogers - I have sent U a PM. Can U pls check ? Thank you

in 12 minutes, Sharon (S) has travelled 14km. So distance between Xin Yi(X) and S is 31km - 14km = 17km. Since S and X are travelling in opposite directions, the distance between them will decrease at a rate of 70km/h +100km/h = 170km/h. So time taken for S and X to meet is 17km / (170km/h) = 1/10h = 10min. So the time they meet is at 10:22am.

Should meet at 10.18am.

oh yah. sry 1/10h is 6min not 10min... XD

For speed questions, I like to see if I can use the speed ratios as they can be quite flexible. In this question, after the first 12 min they travel for the same length of time, so I can leverage the ratios .....